STEPS
1. Initialize the count with 0.
2. Input the string, in this case a[10].
3. Initialize i with 0, check the value at a[i] against the cases mentioned in switch loop.
4. If the value tends to be equal to any of the case labels , increment the count.
5. Increment i by 1 and repeat steps 3 and 4 till a[i] is not equal to '\0' (null).
6. Display count.
PROGRAM
//Program to count the number of vowels in a string
# include<iostream>
using namespace std;
int main()
{
char a[10];
int i,j,count=0;
cin.getline(a,20); //Input the string
for(i=0;a[i]!='\0';i++) // Loop to count the number of vowels
{
switch(a[i])
{
case 'a' : case 'A':
case 'i' : case 'I':
case 'e' : case 'E':
case 'o' : case 'O':
case 'u' : case 'U':
count++ ;
}
}
cout<<count; // Displaying count
return 0;
}
OUTPUT
