PROGRAM
//Program to design a Magic Square.
//Program to design a Magic Square.
#include<iostream>
using namespace std;
int main()
{
int k[4][4],i,j,a,b,c,d,p,h;
int sum1,sum2,sum3,sum4;
char ch='n';
cout<<"ENTER THE VALUES OF a,b,c,d"<<endl;
cout<<"a:";
cin>>a;
cout<<"\nb:";
cin>>b;
cout<<"\nc:";
cin>>c;
cout<<"\nd:";
cin>>d;
cout<<"\nSUM OF ELEMENTS ENTERED(a,b,c,d):"<<(a+b+c+d)<<endl;
cout<<"DESIGNED A MAGICAL SQUARE USING THE ENTERED NUMBERS(a,b,c,d)..." <<endl<<endl;
k[0][0]=a; k[0][1]=b; k[0][2]=c; k[0][3]=d;
k[1][0]=d+1; k[1][1]=c-1; k[1][2]=b-3; k[1][3]=a+3;
k[2][0]=b-2; k[2][1]=a+2; k[2][2]=d+2; k[2][3]=c-2;
k[3][0]=c+1; k[3][1]=d-1; k[3][2]=a+1; k[3][3]=b-1; //Formula for magic square
for(i=0;i<4;i++)
{
for(j=0;j<4;j++)
{
cout<<k[i][j]<<"\t";
}
cout<<endl;
}
cout<<"\nTHIS IS THE MAGICAL SQUARE\n"<<endl;
cout<<"IN THIS MAGICAL SQUARE THE SUM OF ELEMENTS OF EACH ROW\n"<<endl;
cout<<"THE SUM OF ELEMENTS OF EACH COLUMN\n"<<endl;
cout<<"THE SUM OF ELEMENTS OF EACH DIAGONAL\n"<<endl;
cout<<"THE SUM OF ELEMENTS OF MIDDLE SQUARE\n"<<endl;
cout<<"WILL BE SAME. AND IT IS EQUAL TO THE SUM OF THE ELEMENTS ENTERED."<<endl<<endl;
cout<<"LET US SEE..."<<endl;
cout<<"FROM WHERE U WANNA START:\n\n";
do
{
cout<<"1.ROWS\n";
cout<<"2.COLUMNS\n";
cout<<"3.DIAGONALS\n";
cout<<"4.MIDDLE SQUARE\n";
cout<<"ENTER YOUR CHOICE:\n";
cin>>h;
switch(h)
{
case 1:
do
{
cout<<"ROWS\n";
cout<<"WE HAVE 4 ROWS 1,2,3,4. ENTER THE NO OF ROW WHOSE SUM OF ELEMENTS U WANT TO SEE\n";
cin>>p;
switch(p)
{
case 1:
i=0; sum1=0;
for(j=0;j<4;j++)
{
sum1=sum1+k[i][j];
}
cout<<"SUM OF ELEMENTS OF 1ST ROW:"<<sum1<<endl;
break;
case 2:
i=1; sum2=0;
for(j=0;j<4;j++)
{
sum2=sum2+k[i][j];
}
cout<<"SUM OF ELEMENTS OF 2ND ROW:"<<sum2<<endl;
break;
case 3:
i=2; sum3=0;
for(j=0;j<4;j++)
{
sum3=sum3+k[i][j];
}
cout<<"SUM OF ELEMENTS OF 3RD ROW:"<<sum3<<endl;
break;
case 4:
i=3; sum4=0;
for(j=0;j<4;j++)
{
sum4=sum4+k[i][j];
}
cout<<"SUM OF ELEMENTS OF 4Th ROW:"<<sum4<<endl;
break;
default :
cout<<"default";
break;
}
cout<<"DO U WISH TO CONTINUE WITH OTHER ROWS:"<<endl;
cin>>ch;
}while(ch=='Y'||ch=='y');
break;
case 2:
do
{
cout<<"COLUMNS"<<endl;
cout<<"WE HAVE 4 COLUMNS 1,2,3,4. ENTER THE NO OF COLUMN WHOSE SUM OF ELEMENTS YOU WANT TO SEE\n";
cin>>p;
switch(p)
{
case 1:
j=0; sum1=0;
for(i=0;i<4;i++)
{
sum1=k[i][j]+sum1;
}
cout<<"SUM OF ELEMENT OF 1ST COLUMN:"<<sum1<<endl;
break;
case 2:
j=1; sum2=0;
for(i=0;i<4;i++)
{
sum2=k[i][j]+sum2;
}
cout<<"SUM OF ELEMENT OF 2ND COLUMN:"<<sum2<<endl;
break;
case 3:
j=2; sum3=0;
for(i=0;i<4;i++)
{
sum3=k[i][j]+sum3;
}
cout<<"SUM OF ELEMENT OF 3RD COLUMN:"<<sum3<<endl;
break;
case 4:
j=3; sum4=0;
for(i=0;i<4;i++)
{
sum4=k[i][j]+sum4;
}
cout<<"SUM OF ELEMENT OF 4TH COLUMN:"<<sum4<<endl;
break;
default:
cout<<"default";
break;
}
cout<<"DO YOU WISH TO CONTINUE WITH COLUMNS... "<<endl;
cin>>ch;
}while(ch=='Y'||ch=='y');
break;
case 3:
do
{
cout<<"DIAGONALS"<<endl;
cout<<"WE HAVE TWO DIAGONALS 1,2.ENTER THE DIADONAL WHOSE SUM OF ELEMENTS YOU WANT TO SEE\n";
cin>>p;
switch(p)
{
case 1:
sum1=0;
for(i=0,j=0;i<4;i++,j++)
{
sum1=sum1+k[i][j];
}
cout<<"SUM OF ELEMENTS OF 1ST DIAGONAL:"<<sum1<<endl;
break;
case 2:
sum2=0;
for(i=0,j=3;i<4;i++,j--)
{
sum2=sum2+k[i][j];
}
cout<<"SUM OF ELEMENTS OF 1ST DIAGONAL:"<<sum2<<endl;
break;
default :
cout<<"DEFAULT";
break;
}
cout<<"DO WISH TO CONTINUE WITH ANOTHER DIAGONAL..."<<endl;
cin>>ch;
}while(ch=='Y'||ch=='y');
break;
case 4:
sum1=0;
cout<<"MIDDLE INNER SQUARE";
for(i=1;i<3;i++)
{
for(j=1;j<3;j++)
{
sum1=sum1+k[i][j];
}
}
cout<<"SUM OF ELEMENTS OF MIDDLE SQUARE IS:"<<sum1<<endl;
break;
}
cout<<"DO YOU HAVE SOME OTHER CHOICE:"<<endl;
cin>>ch;
}
while(ch=='Y'||ch=='y');
}
OUTPUT
OUTPUT
